3.206 \(\int \sin ^3(a+b x) \sin (c+d x) \, dx\)

Optimal. Leaf size=97 \[ \frac {3 \sin (a+x (b-d)-c)}{8 (b-d)}-\frac {\sin (3 a+x (3 b-d)-c)}{8 (3 b-d)}-\frac {3 \sin (a+x (b+d)+c)}{8 (b+d)}+\frac {\sin (3 a+x (3 b+d)+c)}{8 (3 b+d)} \]

[Out]

3/8*sin(a-c+(b-d)*x)/(b-d)-1/8*sin(3*a-c+(3*b-d)*x)/(3*b-d)-3/8*sin(a+c+(b+d)*x)/(b+d)+1/8*sin(3*a+c+(3*b+d)*x
)/(3*b+d)

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Rubi [A]  time = 0.07, antiderivative size = 97, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 2, integrand size = 15, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.133, Rules used = {4569, 2637} \[ \frac {3 \sin (a+x (b-d)-c)}{8 (b-d)}-\frac {\sin (3 a+x (3 b-d)-c)}{8 (3 b-d)}-\frac {3 \sin (a+x (b+d)+c)}{8 (b+d)}+\frac {\sin (3 a+x (3 b+d)+c)}{8 (3 b+d)} \]

Antiderivative was successfully verified.

[In]

Int[Sin[a + b*x]^3*Sin[c + d*x],x]

[Out]

(3*Sin[a - c + (b - d)*x])/(8*(b - d)) - Sin[3*a - c + (3*b - d)*x]/(8*(3*b - d)) - (3*Sin[a + c + (b + d)*x])
/(8*(b + d)) + Sin[3*a + c + (3*b + d)*x]/(8*(3*b + d))

Rule 2637

Int[sin[Pi/2 + (c_.) + (d_.)*(x_)], x_Symbol] :> Simp[Sin[c + d*x]/d, x] /; FreeQ[{c, d}, x]

Rule 4569

Int[Sin[v_]^(p_.)*Sin[w_]^(q_.), x_Symbol] :> Int[ExpandTrigReduce[Sin[v]^p*Sin[w]^q, x], x] /; ((PolynomialQ[
v, x] && PolynomialQ[w, x]) || (BinomialQ[{v, w}, x] && IndependentQ[Cancel[v/w], x])) && IGtQ[p, 0] && IGtQ[q
, 0]

Rubi steps

\begin {align*} \int \sin ^3(a+b x) \sin (c+d x) \, dx &=\int \left (\frac {3}{8} \cos (a-c+(b-d) x)-\frac {1}{8} \cos (3 a-c+(3 b-d) x)-\frac {3}{8} \cos (a+c+(b+d) x)+\frac {1}{8} \cos (3 a+c+(3 b+d) x)\right ) \, dx\\ &=-\left (\frac {1}{8} \int \cos (3 a-c+(3 b-d) x) \, dx\right )+\frac {1}{8} \int \cos (3 a+c+(3 b+d) x) \, dx+\frac {3}{8} \int \cos (a-c+(b-d) x) \, dx-\frac {3}{8} \int \cos (a+c+(b+d) x) \, dx\\ &=\frac {3 \sin (a-c+(b-d) x)}{8 (b-d)}-\frac {\sin (3 a-c+(3 b-d) x)}{8 (3 b-d)}-\frac {3 \sin (a+c+(b+d) x)}{8 (b+d)}+\frac {\sin (3 a+c+(3 b+d) x)}{8 (3 b+d)}\\ \end {align*}

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Mathematica [A]  time = 0.54, size = 91, normalized size = 0.94 \[ \frac {1}{8} \left (\frac {3 \sin (a+b x-c-d x)}{b-d}-\frac {\sin (3 a+3 b x-c-d x)}{3 b-d}+\frac {\sin (3 a+3 b x+c+d x)}{3 b+d}-\frac {3 \sin (a+x (b+d)+c)}{b+d}\right ) \]

Antiderivative was successfully verified.

[In]

Integrate[Sin[a + b*x]^3*Sin[c + d*x],x]

[Out]

((3*Sin[a - c + b*x - d*x])/(b - d) - Sin[3*a - c + 3*b*x - d*x]/(3*b - d) + Sin[3*a + c + 3*b*x + d*x]/(3*b +
d) - (3*Sin[a + c + (b + d)*x])/(b + d))/8

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fricas [A]  time = 0.56, size = 115, normalized size = 1.19 \[ \frac {{\left (7 \, b^{2} d - d^{3} - {\left (b^{2} d - d^{3}\right )} \cos \left (b x + a\right )^{2}\right )} \cos \left (d x + c\right ) \sin \left (b x + a\right ) + 3 \, {\left ({\left (b^{3} - b d^{2}\right )} \cos \left (b x + a\right )^{3} - {\left (3 \, b^{3} - b d^{2}\right )} \cos \left (b x + a\right )\right )} \sin \left (d x + c\right )}{9 \, b^{4} - 10 \, b^{2} d^{2} + d^{4}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(sin(b*x+a)^3*sin(d*x+c),x, algorithm="fricas")

[Out]

((7*b^2*d - d^3 - (b^2*d - d^3)*cos(b*x + a)^2)*cos(d*x + c)*sin(b*x + a) + 3*((b^3 - b*d^2)*cos(b*x + a)^3 -
(3*b^3 - b*d^2)*cos(b*x + a))*sin(d*x + c))/(9*b^4 - 10*b^2*d^2 + d^4)

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giac [A]  time = 1.46, size = 89, normalized size = 0.92 \[ \frac {\sin \left (3 \, b x + d x + 3 \, a + c\right )}{8 \, {\left (3 \, b + d\right )}} - \frac {\sin \left (3 \, b x - d x + 3 \, a - c\right )}{8 \, {\left (3 \, b - d\right )}} - \frac {3 \, \sin \left (b x + d x + a + c\right )}{8 \, {\left (b + d\right )}} + \frac {3 \, \sin \left (b x - d x + a - c\right )}{8 \, {\left (b - d\right )}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(sin(b*x+a)^3*sin(d*x+c),x, algorithm="giac")

[Out]

1/8*sin(3*b*x + d*x + 3*a + c)/(3*b + d) - 1/8*sin(3*b*x - d*x + 3*a - c)/(3*b - d) - 3/8*sin(b*x + d*x + a +
c)/(b + d) + 3/8*sin(b*x - d*x + a - c)/(b - d)

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maple [A]  time = 0.99, size = 90, normalized size = 0.93 \[ \frac {3 \sin \left (a -c +\left (b -d \right ) x \right )}{8 \left (b -d \right )}-\frac {\sin \left (3 a -c +\left (3 b -d \right ) x \right )}{8 \left (3 b -d \right )}-\frac {3 \sin \left (a +c +\left (b +d \right ) x \right )}{8 \left (b +d \right )}+\frac {\sin \left (3 a +c +\left (3 b +d \right ) x \right )}{24 b +8 d} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(sin(b*x+a)^3*sin(d*x+c),x)

[Out]

3/8*sin(a-c+(b-d)*x)/(b-d)-1/8*sin(3*a-c+(3*b-d)*x)/(3*b-d)-3/8*sin(a+c+(b+d)*x)/(b+d)+1/8*sin(3*a+c+(3*b+d)*x
)/(3*b+d)

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maxima [B]  time = 0.40, size = 789, normalized size = 8.13 \[ \text {result too large to display} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(sin(b*x+a)^3*sin(d*x+c),x, algorithm="maxima")

[Out]

-1/16*((3*b^3*sin(c) - b^2*d*sin(c) - 3*b*d^2*sin(c) + d^3*sin(c))*cos((3*b + d)*x + 3*a + 2*c) - (3*b^3*sin(c
) - b^2*d*sin(c) - 3*b*d^2*sin(c) + d^3*sin(c))*cos((3*b + d)*x + 3*a) + (3*b^3*sin(c) + b^2*d*sin(c) - 3*b*d^
2*sin(c) - d^3*sin(c))*cos(-(3*b - d)*x - 3*a + 2*c) - (3*b^3*sin(c) + b^2*d*sin(c) - 3*b*d^2*sin(c) - d^3*sin
(c))*cos(-(3*b - d)*x - 3*a) - 3*(9*b^3*sin(c) - 9*b^2*d*sin(c) - b*d^2*sin(c) + d^3*sin(c))*cos((b + d)*x + a
+ 2*c) + 3*(9*b^3*sin(c) - 9*b^2*d*sin(c) - b*d^2*sin(c) + d^3*sin(c))*cos((b + d)*x + a) - 3*(9*b^3*sin(c) +
9*b^2*d*sin(c) - b*d^2*sin(c) - d^3*sin(c))*cos(-(b - d)*x - a + 2*c) + 3*(9*b^3*sin(c) + 9*b^2*d*sin(c) - b*
d^2*sin(c) - d^3*sin(c))*cos(-(b - d)*x - a) - (3*b^3*cos(c) - b^2*d*cos(c) - 3*b*d^2*cos(c) + d^3*cos(c))*sin
((3*b + d)*x + 3*a + 2*c) - (3*b^3*cos(c) - b^2*d*cos(c) - 3*b*d^2*cos(c) + d^3*cos(c))*sin((3*b + d)*x + 3*a)
- (3*b^3*cos(c) + b^2*d*cos(c) - 3*b*d^2*cos(c) - d^3*cos(c))*sin(-(3*b - d)*x - 3*a + 2*c) - (3*b^3*cos(c) +
b^2*d*cos(c) - 3*b*d^2*cos(c) - d^3*cos(c))*sin(-(3*b - d)*x - 3*a) + 3*(9*b^3*cos(c) - 9*b^2*d*cos(c) - b*d^
2*cos(c) + d^3*cos(c))*sin((b + d)*x + a + 2*c) + 3*(9*b^3*cos(c) - 9*b^2*d*cos(c) - b*d^2*cos(c) + d^3*cos(c)
)*sin((b + d)*x + a) + 3*(9*b^3*cos(c) + 9*b^2*d*cos(c) - b*d^2*cos(c) - d^3*cos(c))*sin(-(b - d)*x - a + 2*c)
+ 3*(9*b^3*cos(c) + 9*b^2*d*cos(c) - b*d^2*cos(c) - d^3*cos(c))*sin(-(b - d)*x - a))/(9*b^4*cos(c)^2 + 9*b^4*
sin(c)^2 + (cos(c)^2 + sin(c)^2)*d^4 - 10*(b^2*cos(c)^2 + b^2*sin(c)^2)*d^2)

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mupad [B]  time = 1.72, size = 494, normalized size = 5.09 \[ {\mathrm {e}}^{a\,3{}\mathrm {i}-c\,1{}\mathrm {i}+b\,x\,3{}\mathrm {i}-d\,x\,1{}\mathrm {i}}\,\left (\frac {-3\,b^3-b^2\,d+3\,b\,d^2+d^3}{b^4\,144{}\mathrm {i}-b^2\,d^2\,160{}\mathrm {i}+d^4\,16{}\mathrm {i}}+\frac {{\mathrm {e}}^{-a\,6{}\mathrm {i}-b\,x\,6{}\mathrm {i}}\,\left (-3\,b^3+b^2\,d+3\,b\,d^2-d^3\right )}{b^4\,144{}\mathrm {i}-b^2\,d^2\,160{}\mathrm {i}+d^4\,16{}\mathrm {i}}-\frac {{\mathrm {e}}^{-a\,2{}\mathrm {i}-b\,x\,2{}\mathrm {i}}\,\left (-27\,b^3-27\,b^2\,d+3\,b\,d^2+3\,d^3\right )}{b^4\,144{}\mathrm {i}-b^2\,d^2\,160{}\mathrm {i}+d^4\,16{}\mathrm {i}}-\frac {{\mathrm {e}}^{-a\,4{}\mathrm {i}-b\,x\,4{}\mathrm {i}}\,\left (-27\,b^3+27\,b^2\,d+3\,b\,d^2-3\,d^3\right )}{b^4\,144{}\mathrm {i}-b^2\,d^2\,160{}\mathrm {i}+d^4\,16{}\mathrm {i}}\right )-{\mathrm {e}}^{a\,3{}\mathrm {i}+c\,1{}\mathrm {i}+b\,x\,3{}\mathrm {i}+d\,x\,1{}\mathrm {i}}\,\left (\frac {-3\,b^3+b^2\,d+3\,b\,d^2-d^3}{b^4\,144{}\mathrm {i}-b^2\,d^2\,160{}\mathrm {i}+d^4\,16{}\mathrm {i}}+\frac {{\mathrm {e}}^{-a\,6{}\mathrm {i}-b\,x\,6{}\mathrm {i}}\,\left (-3\,b^3-b^2\,d+3\,b\,d^2+d^3\right )}{b^4\,144{}\mathrm {i}-b^2\,d^2\,160{}\mathrm {i}+d^4\,16{}\mathrm {i}}-\frac {{\mathrm {e}}^{-a\,2{}\mathrm {i}-b\,x\,2{}\mathrm {i}}\,\left (-27\,b^3+27\,b^2\,d+3\,b\,d^2-3\,d^3\right )}{b^4\,144{}\mathrm {i}-b^2\,d^2\,160{}\mathrm {i}+d^4\,16{}\mathrm {i}}-\frac {{\mathrm {e}}^{-a\,4{}\mathrm {i}-b\,x\,4{}\mathrm {i}}\,\left (-27\,b^3-27\,b^2\,d+3\,b\,d^2+3\,d^3\right )}{b^4\,144{}\mathrm {i}-b^2\,d^2\,160{}\mathrm {i}+d^4\,16{}\mathrm {i}}\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(sin(a + b*x)^3*sin(c + d*x),x)

[Out]

exp(a*3i - c*1i + b*x*3i - d*x*1i)*((3*b*d^2 - b^2*d - 3*b^3 + d^3)/(b^4*144i + d^4*16i - b^2*d^2*160i) + (exp
(- a*6i - b*x*6i)*(3*b*d^2 + b^2*d - 3*b^3 - d^3))/(b^4*144i + d^4*16i - b^2*d^2*160i) - (exp(- a*2i - b*x*2i)
*(3*b*d^2 - 27*b^2*d - 27*b^3 + 3*d^3))/(b^4*144i + d^4*16i - b^2*d^2*160i) - (exp(- a*4i - b*x*4i)*(3*b*d^2 +
27*b^2*d - 27*b^3 - 3*d^3))/(b^4*144i + d^4*16i - b^2*d^2*160i)) - exp(a*3i + c*1i + b*x*3i + d*x*1i)*((3*b*d
^2 + b^2*d - 3*b^3 - d^3)/(b^4*144i + d^4*16i - b^2*d^2*160i) + (exp(- a*6i - b*x*6i)*(3*b*d^2 - b^2*d - 3*b^3
+ d^3))/(b^4*144i + d^4*16i - b^2*d^2*160i) - (exp(- a*2i - b*x*2i)*(3*b*d^2 + 27*b^2*d - 27*b^3 - 3*d^3))/(b
^4*144i + d^4*16i - b^2*d^2*160i) - (exp(- a*4i - b*x*4i)*(3*b*d^2 - 27*b^2*d - 27*b^3 + 3*d^3))/(b^4*144i + d
^4*16i - b^2*d^2*160i))

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sympy [A]  time = 31.74, size = 933, normalized size = 9.62 \[ \text {result too large to display} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(sin(b*x+a)**3*sin(d*x+c),x)

[Out]

Piecewise((x*sin(a)**3*sin(c), Eq(b, 0) & Eq(d, 0)), (3*x*sin(a - d*x)**3*sin(c + d*x)/8 - 3*x*sin(a - d*x)**2
*cos(a - d*x)*cos(c + d*x)/8 + 3*x*sin(a - d*x)*sin(c + d*x)*cos(a - d*x)**2/8 - 3*x*cos(a - d*x)**3*cos(c + d
*x)/8 + sin(a - d*x)**3*cos(c + d*x)/(8*d) + 3*sin(a - d*x)**2*sin(c + d*x)*cos(a - d*x)/(4*d) + 3*sin(c + d*x
)*cos(a - d*x)**3/(8*d), Eq(b, -d)), (x*sin(a - d*x/3)**3*sin(c + d*x)/8 - 3*x*sin(a - d*x/3)**2*cos(a - d*x/3
)*cos(c + d*x)/8 - 3*x*sin(a - d*x/3)*sin(c + d*x)*cos(a - d*x/3)**2/8 + x*cos(a - d*x/3)**3*cos(c + d*x)/8 -
9*sin(a - d*x/3)**3*cos(c + d*x)/(8*d) - 3*sin(a - d*x/3)**2*sin(c + d*x)*cos(a - d*x/3)/(4*d) - sin(c + d*x)*
cos(a - d*x/3)**3/(8*d), Eq(b, -d/3)), (x*sin(a + d*x/3)**3*sin(c + d*x)/8 + 3*x*sin(a + d*x/3)**2*cos(a + d*x
/3)*cos(c + d*x)/8 - 3*x*sin(a + d*x/3)*sin(c + d*x)*cos(a + d*x/3)**2/8 - x*cos(a + d*x/3)**3*cos(c + d*x)/8
- 9*sin(a + d*x/3)**3*cos(c + d*x)/(8*d) + 3*sin(a + d*x/3)**2*sin(c + d*x)*cos(a + d*x/3)/(4*d) + sin(c + d*x
)*cos(a + d*x/3)**3/(8*d), Eq(b, d/3)), (3*x*sin(a + d*x)**3*sin(c + d*x)/8 + 3*x*sin(a + d*x)**2*cos(a + d*x)
*cos(c + d*x)/8 + 3*x*sin(a + d*x)*sin(c + d*x)*cos(a + d*x)**2/8 + 3*x*cos(a + d*x)**3*cos(c + d*x)/8 - 5*sin
(a + d*x)**3*cos(c + d*x)/(8*d) - 3*sin(a + d*x)*cos(a + d*x)**2*cos(c + d*x)/(4*d) + 3*sin(c + d*x)*cos(a + d
*x)**3/(8*d), Eq(b, d)), (-9*b**3*sin(a + b*x)**2*sin(c + d*x)*cos(a + b*x)/(9*b**4 - 10*b**2*d**2 + d**4) - 6
*b**3*sin(c + d*x)*cos(a + b*x)**3/(9*b**4 - 10*b**2*d**2 + d**4) + 7*b**2*d*sin(a + b*x)**3*cos(c + d*x)/(9*b
**4 - 10*b**2*d**2 + d**4) + 6*b**2*d*sin(a + b*x)*cos(a + b*x)**2*cos(c + d*x)/(9*b**4 - 10*b**2*d**2 + d**4)
+ 3*b*d**2*sin(a + b*x)**2*sin(c + d*x)*cos(a + b*x)/(9*b**4 - 10*b**2*d**2 + d**4) - d**3*sin(a + b*x)**3*co
s(c + d*x)/(9*b**4 - 10*b**2*d**2 + d**4), True))

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